Question:hard

The major product ‘B’ of the following reaction sequence is

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Hydroboration oxidation gives anti-Markovnikov alcohol. In terminal alkenes, the \(-OH\) group is added to the less substituted carbon.
Updated On: Jun 26, 2026
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The Correct Option is D

Solution and Explanation

Step 1: Step 1 of reaction -- HBr on 1-phenylethanol.
1-Phenylethanol (C\(_6\)H\(_5\)CH(OH)CH\(_3\)) reacts with HBr: OH is replaced by Br giving C\(_6\)H\(_5\)CHBrCH\(_3\) (1-bromo-1-phenylethane).

Step 2: Step 2 -- alcoholic KOH (elimination).
Alcoholic KOH causes dehydrohalogenation (E2). The major product is styrene (C\(_6\)H\(_5\)CH=CH\(_2\)) via Zaitsev elimination. This corresponds to product 4. \[ oxed{4} \]
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