Question

The magnetic moment of \(Cr^{3+}\) ion is \(3.87\ \text{BM}\). The number of unpaired electrons present is:

• A. \(1\)
• B. \(2\)
• C. \(3\)
• D. \(4\)

Hint:

Important spin-only magnetic moments:
• \(1\) unpaired electron \(\rightarrow 1.73\ \text{BM}\)
• \(2\) unpaired electrons \(\rightarrow 2.83\ \text{BM}\)
• \(3\) unpaired electrons \(\rightarrow 3.87\ \text{BM}\)
• \(4\) unpaired electrons \(\rightarrow 4.90\ \text{BM}\)
• \(5\) unpaired electrons \(\rightarrow 5.92\ \text{BM}\) These values are frequently used directly in competitive exams.

Answer 1

The Correct Option is C