Question:medium

The magnetic force on a current carrying wire of length $l$, placed in a uniform magnetic field ($B$) if the wire is oriented perpendicular to magnetic field, is \dots

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The magnetic force becomes maximum when the conductor is perpendicular to the magnetic field because: \[ \sin 90^\circ = 1 \]
Updated On: May 18, 2026
  • 0
  • $ILB$
  • $2ILB$
  • $\frac{ILB}{2}$
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The Correct Option is B

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