Question:easy

The magnetic field intensity (H) at the centre of a long solenoid having 'n' turns per unit length and carrying a current I, when no material is kept in it is (\(μ_0\) = permeability of free space)

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H equals turns per unit length times current.
Updated On: Oct 1, 2026
  • \(n/I\)
  • \(nI\)
  • \(μ_0I\)
  • \(μ_0/nI\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Ampere circuital law
A loop of length $l$ along the axis encloses $nlI$. Then $H l = nlI$, so $H = nI$. Option (B).

Final Answer:
nI. \[ \boxed{\text{(B)}\ nI} \]
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