Step 1: Read off the magnetic field part.
The given field is $B_y = 2\times10^{-7}\sin(0.5\times10^3 x + 1.5\times10^{11} t)$, so the amplitude is $B_0 = 2\times10^{-7}\,\text{T}$ and the field points along $y$.
Step 2: Get the electric field amplitude.
In an electromagnetic wave the field amplitudes are tied by $E_0 = cB_0$. So \[ E_0 = (3\times10^8)(2\times10^{-7}) = 60\ \text{V/m}. \]
Step 3: Decide the direction of $E$.
The fields $\vec{E}$, $\vec{B}$ and the propagation direction form a right-handed set, with propagation along $\vec{E}\times\vec{B}$. With $\vec{B}$ along $y$, the electric field must be along $z$. So we expect an $E_z$ form, which rules out the $E_y$ options.
Step 4: Match the phase correctly.
$E$ and $B$ stay in phase and share the same wave number and frequency. The correct listed expression keeps the $0.5\times10^3$ and $1.5\times10^{11}$ values and uses a sine, matching the field form.
Step 5: Pick the right option.
The expression with $E_0 = 60$, along $z$, and the same magnitudes is $E_z = 60\sin(0.5\times10^3 x - 1.5\times10^{11} t)$.
Step 6: Conclusion.
The electric field is \[ \boxed{E_z = 60\sin(0.5\times10^3 x - 1.5\times10^{11} t)} \]