To determine the correct expression for the Lucas sequence \(L_n\), let's examine the recurrence relation and given options:
The Lucas sequence is defined as: \[ L_n = L_{n-1} + L_{n-2} \, \text{for } n \geq 3 \] with initial conditions: \(L_1 = 1\) and \(L_2 = 3\).
This is similar to the Fibonacci sequence but starts with different initial values. The Lucas sequence has a closed-form expression involving the golden ratio \(\phi\) and its conjugate.
Recall that the closed-form expressions for such sequences involve the roots of the characteristic equation. The characteristic equation for the recurrence relation above is: \[ x^2 = x + 1 \Rightarrow x^2 - x - 1 = 0 \]
Solving this quadratic equation gives two roots: \[ \phi = \frac{1+\sqrt{5}}{2} \quad \text{and} \quad \psi = \frac{1-\sqrt{5}}{2} \]
These are the same roots used in the closed-form solution for the Fibonacci sequence. The closed-form expression for the Lucas sequence is: \[ L_n = \phi^n + \psi^n \]
Now, let's check the given options:
The correct option is: \( L_n = \left(\tfrac{1+\sqrt{5}}{2}\right)^n + \left(\tfrac{1-\sqrt{5}}{2}\right)^n \)
Let \(A\) be the adjacency matrix of the given graph with vertices \(\{1,2,3,4,5\}\). 
Let \(\lambda_1, \lambda_2, \lambda_3, \lambda_4, \lambda_5\) be the eigenvalues of \(A\) (not necessarily distinct). Find: \[ \lambda_1 + \lambda_2 + \lambda_3 + \lambda_4 + \lambda_5 \;=\; \_\_\_\_\_\_ . \]
The output of a 2-input multiplexer is connected back to one of its inputs as shown in the figure. Match the functional equivalence of this circuit to one of the following options. 