Step 1: Find intersection attempt:
Equate: $1 - s = 1 + t$, $-2 + s = -2 + t$, $3 - 2s = -1 - 2t$.
Step 2: Solve:
From the first, $s = -t$. From the second, $s = t$, so $s = t = 0$. Third: $3 = -1$, which is false.
Step 3: Conclusion:
No common point exists, and the directions are not parallel, so the lines are skew, option (D).
Final Answer:
The lines are skew.
\[ \boxed{\text{(D) }\text{skew lines}} \]