Question:medium
The line segment joining the points $(-3,\,1)$ and $(1,\,1)$ is the transverse axis of a hyperbola. If the length of the conjugate axis is 4, then the equation of the hyperbola is
The line segment joining the points $(-3,\,1)$ and $(1,\,1)$ is the transverse axis of a hyperbola. If the length of the conjugate axis is 4, then the equation of the hyperbola is
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The transverse axis of a hyperbola connects the two vertices. Its midpoint is the centre. Always identify whether the transverse axis is horizontal or vertical before writing the standard form.
Updated On: Apr 25, 2026
- $(x+2)^2 - (y-1)^2 = 4$
- $(x+1)^2 - (y-1)^2 = 16$
- $(x+1)^2 - (y-1)^2 = 4$
- $(x+2)^2 - (y-1)^2 = 16$
- $(x-1)^2 - (y+1)^2 = 4$
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The Correct Option is C
Solution and Explanation
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