Question:medium

The length of the latus rectum and eccentricity of the Hyperbola \(9x^2-16y^2=144\) are

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For \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\), use \(e=\sqrt{1+\frac{b^2}{a^2}}\) and latus rectum \(=\frac{2b^2}{a}\).
  • \(\left(\frac{9}{4},\frac{5}{4}\right)\)
  • \(\left(\frac{9}{2},\frac{5}{4}\right)\)
  • \(\left(\frac{9}{2},\frac{5}{2}\right)\)
  • \(\left(9,\frac{5}{2}\right)\)
Show Solution

The Correct Option is B

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