Question

The length of Burgers vector b in copper (Cu), which has an FCC crystal structure, is

• A. b = 0.25563 nm
• B. b = 1.25563 nm
• C. b = 2.25563 nm
• D. b = 1.325563 nm

Hint:

FCC crystals have closely packed structures. The Burgers vector is always proportional to the lattice parameter a.

Answer 1

The Correct Option is A

In FCC structures, the Burgers vector `b` is determined by the formula `\[b = a \sqrt{\frac{1}{2}}\]`, where `\(a\)` denotes the lattice parameter. For example, using copper's lattice parameter of `0.361 \, \text{nm}`, the Burgers vector is calculated as `\[b = 0.361 \, \text{nm} \times \sqrt{\frac{1}{2}} \approx 0.25563 \, \text{nm}\]`.