Question:medium

Find the Laurent series of the function \[ f(z)=1+\frac{3}{z+2}-\frac{8}{z+3} \] in the region \[ |z|<2. \] 

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Always look closely at the convergence condition! To ensure your geometric series converges (\( |t| < 1 \)), always factor out the larger value in magnitude between the variable \( z \) and the constant term.
Updated On: Jul 9, 2026
  • \( \frac{3}{2}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{3}\right)^n - \frac{8}{3}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{2}\right)^n \)
  • \( 1 + \frac{3}{2}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{2}\right)^n - \frac{8}{3}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{2}\right)^n \)
  • \( 1 + \frac{3}{2}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{2}\right)^n - \frac{8}{3}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{3}\right)^n \)
  • \( \frac{3}{2}\sum_{n=0}^{\infty}\left(\frac{z}{2}\right)^n(-1)^n - \frac{8}{3}\sum_{n=0}^{\infty}(-1)^n\left(\frac{z}{3}\right)^n \)
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The Correct Option is C

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