Question

The IUPAC name of the coordination compound is: \[ [\text{Rh}(CO)_2I_2]^- \]

• A. dicarbonylidiodidohorodate(I)
• B. dicarbonylidiodidohorodate(I)
• C. carbonylbisiodidorhodium(I)
• D. carbonylidiodiderhodium(I)

Hint:

When naming coordination compounds, the ligands are named alphabetically, and prefixes like "bis" are used when there are multiple identical ligands.

Answer 1

The Correct Option is C

Step 1: Analyze the Coordination Complex.
The coordination compound is \( [\text{Rh}(CO)_2I_2]^-\). It consists of:- Two carbonyl (\(CO\)) ligands.- Two iodido (\(I\)) ligands.- The central metal ion is rhodium (Rh) in the \(+1\) oxidation state.

Step 2: IUPAC Naming Conventions.
- The metal is named "rhodium" and its oxidation state is denoted as \( \text{Rh}(I) \) using Roman numerals.- Ligands are listed alphabetically. "Carbonyl" (CO) comes before "iodido" (I).- The prefix "bis" is employed for two identical ligands, specifically the iodido ligands here.

Step 3: Conclusion.
Consequently, the IUPAC name is "carbonylbisiodidorhodium(I)", which matches option (3).