Question

The IUPAC name of an element with atomic number 119 is:

• A. Ununennium
• B. Unnilennium
• C. Unununium
• D. ununoctium

Hint:

To never forget the roots: 0 is Nil (nothing), 1 is Un (uni-), 2 is Bi (bi-), and 9 is Enn (think of 'enneagon' for a 9-sided shape). Just string them together and add "-ium"!

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
IUPAC uses a systematic nomenclature for elements with \( Z>100 \). Names are derived from the digits of the atomic number using specific numerical roots.
Key Formula or Approach:
Roots: 0 = nil, 1 = un, 2 = bi, 3 = tri, 4 = quad, 5 = pent, 6 = hex, 7 = sept, 8 = oct, 9 = enn.
The name is formed by joining the roots and adding "-ium".
Step 2: Detailed Explanation:
For \( Z = 119 \):
- First digit (1) \( \to \) un
- Second digit (1) \( \to \) un
- Third digit (9) \( \to \) enn
Concatenation: un \( + \) un \( + \) enn \( + \) ium \( = \) Ununennium.
Note: If the last digit root is "enn" and the suffix is "ium", we keep all three 'n's. If the root is "bi" or "tri", one 'i' is dropped.
Step 3: Final Answer:
The name is Ununennium.