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The interval containing all the solutions of the inequality \[ \sqrt{x^2-12x+48}\lt 2x+3 \] only is

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For inequalities involving square roots, first ensure that the right-hand side is positive before squaring. After solving the resulting quadratic inequality, always check the obtained solutions against the original restriction.

Updated On: Oct 7, 2026

$(-\infty,-\sqrt{29}-4)\cup(\sqrt{29}-4,\infty)$
$(-\infty,-\sqrt{29}-4)$
$(\sqrt{29}-4,\infty)$
$(-\sqrt{29}-4,\sqrt{29}-4)$

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The Correct Option is C

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The interval containing all the solutions of the inequality \[ \sqrt{x^2-12x+48}\lt 2x+3 \] only is

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The Correct Option is C

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