To solve this question, we need to analyze each statement given in the options and identify any inconsistencies based on chemical reactivity principles.
Chlorine gas (\(Cl_2\)) is less reactive compared to chlorine monofluoride (\(ClF\)) due to the higher bond energy and stability of \(Cl_2\). Generally, interhalogen compounds like \(ClF\) are more reactive than diatomic halogen molecules such as \(Cl_2\). Therefore, this statement is incorrect.
Fluorine (\(F_2\)) is one of the most reactive elements due to its high electronegativity and small atomic size. It can react vigorously with nearly all other elements, including chlorine monofluoride (\(ClF\)). Therefore, this statement is true.
When chlorine monofluoride (\(ClF\)) undergoes hydrolysis, it forms hypochlorous acid (\(HOCl\)) and hydrofluoric acid (\(HF\)). The reaction can be represented as:
ClF + H_2O \rightarrow HOCl + HF
This statement is true.
Fluorine (\(F_2\)) is indeed a stronger oxidizing agent than chlorine (\(Cl_2\)) in aqueous solution. Fluorine has a higher standard reduction potential compared to chlorine, making it more efficient at gaining electrons. Thus, this statement is true.
Based on the analysis above, the correct answer is that the first statement is incorrect: "\(Cl_2\) is more reactive than \(ClF\)". This is contrary to the known reactivity of interhalogen compounds.
Consider the following sequence of reactions:
4-nitrotoluene
Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce_______ mg of B. (Given molar mass in g mol⁻¹ H: 1, C: 12, N: 14, O: 16, Br: 80)}