The problem involves the decay of a radioactive isotope, and we need to calculate the age of a rock based on the given ratio of isotopes $X$ and $Y$. Here’s how to solve it:
- The radioactive isotope $X$ decays into a stable element $Y$. The half-life of $X$ is given as 50 years.
- In the problem, the ratio of the remaining $X$ to the produced element $Y$ is 1:15. This implies that for every 1 part of $X$ that remains, there are 15 parts of $Y$ that have been produced.
- This ratio also implies that the original quantity of $X$ would have been 16 parts in total (1 part remaining + 15 parts decayed).
- The amount of $X$ remaining is 1/16 of the original. This situation after $n$ half-lives can be expressed using the formula for radioactive decay:
- Where \(N\) is the final amount, \(N_0\) is the initial amount, and \(n\) is the number of half-lives.
- Here, \(\frac{1}{16} = \left( \frac{1}{2} \right)^n\).
- Solving for \(n\) requires considering that \(\left( \frac{1}{2} \right)^4 = \frac{1}{16}\):
- This implies \(n = 4\) half-lives.
- The half-life of the isotope $X$ is 50 years, so the total age of the rock is:
- Thus, the age of the rock is estimated to be 200 years.
Therefore, the correct answer is 200 years.