Question:easy

The half-life of a first-order reaction is \(20\) minutes. What is the rate constant (in min\(^{-1}\)) for this reaction?

Show Hint

Use \(k = 0.693/t_{1/2}\).
Updated On: Oct 1, 2026
  • \(0.0347\)
  • \(0.5\)
  • \(13.86\)
  • \(34.67\)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Via the integrated law:
At the half life, $[A] = [A]_0/2$, so $kt_{1/2} = \ln 2$.
\[ k = \frac{\ln 2}{20} = \frac{0.6931}{20} = 0.0347\ \text{min}^{-1} \]

Final Answer:
The rate constant is $0.0347$ min$^{-1}$, option (A). \[ \boxed{0.0347\ \text{min}^{-1}} \]
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