A gravity-controlled instrument's scale is "crowded" precisely because the relationship between current and deflection angle is non-linear — equal increases in current do not produce equal increases in angle. Since \( \sin\theta \) increases very gradually near \( \theta = 0^\circ \) but more rapidly as \( \theta \) approaches 90°, equal steps in current correspond to progressively larger angle changes, bunching up the low readings on the scale.
The non-linear behavior of \( \sin\theta \) explains why the scale of a gravity-controlled instrument is crowded.
Therefore, the correct answer is sine of deflection angle.
It helps to contrast this with spring-controlled instruments, where the controlling torque from a spring is directly proportional to the deflection angle itself (\( T_c \propto \theta \)), which — when balanced against a current-proportional deflecting torque — gives a UNIFORM scale. Gravity control behaves differently because its restoring torque depends on \( \sin\theta \), not \( \theta \) directly, which is what produces the characteristic crowded (non-uniform) scale unique to gravity-controlled instruments. Let's check each option against this comparison.
Comparing with spring control confirms that gravity-controlled instruments crowd their scale because current is proportional to the sine of the deflection angle.
Therefore, the correct answer is sine of deflection angle.