Question:medium

The general solution of the equation \(\tan^2x=1\) is

Show Hint

If \(\tan^2x=1\), then \(\tan x=\pm1\). Therefore, the general solution is \(x=n\pi\pm\frac{\pi}{4}\).
  • \(n\pi+\frac{\pi}{4}\) only
  • \(n\pi\pm\frac{\pi}{4}\)
  • \(2n\pi\pm\frac{\pi}{4}\)
  • \(n\pi-\frac{\pi}{4}\) only
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0