The general combustion equation for any alkane is given by the following equation: \(C_nH_{2n+2} + X O_2 \to nCO_2 + (n+1) H_2O\). What is the value of ‘X’ in the above equation?
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For any hydrocarbon \(C_xH_y\), the balanced oxygen coefficient is always \(x + y/4\). For alkanes, \(x=n\) and \(y=2n+2\). So, \(n + (2n+2)/4 = n + (n+1)/2 = (3n+1)/2\).