Question:medium

The fundamental frequency and peak voltage of an inverter are f and \(\text{V}_\text{m}\) respectively. When it contains all odd harmonics, then its frequency and rms voltage of \(5^{\text{th}}\) harmonic are

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Harmonic Rule of Thumb: - Frequency always scales up: \( f_n = n \cdot f \) - Amplitude always scales down: \( \text{RMS}_n = \frac{V_{\text{peak}, n}}{\sqrt{2}} = \frac{V_m}{n\sqrt{2}} \) For \(n=5\), this gives \(5f\) and \(\frac{V_m}{5\sqrt{2}}\) instantly!

Updated On: Jun 25, 2026

\( 5f \text{ and } \frac{5V_m}{\sqrt{2}} \text{ respectively} \)
\( \frac{f}{5} \text{ and } \frac{V_m}{5} \text{ respectively} \)
\( \frac{f}{5} \text{ and } \frac{V_m}{5\sqrt{2}} \text{ respectively} \)
\( 5f \text{ and } \frac{V_m}{5\sqrt{2}} \text{ respectively} \)

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The Correct Option is D

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