Question:medium
The function $f : A \to B$ given by $f(x) = x, x \in A$, is one to one but not onto. Then:
The function $f : A \to B$ given by $f(x) = x, x \in A$, is one to one but not onto. Then:
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For $f(x)=x$, the function behaves like an identity mapping.
• Onto $\Rightarrow A = B$
• Not onto $\Rightarrow A$ is a proper subset of $B$
• Onto $\Rightarrow A = B$
• Not onto $\Rightarrow A$ is a proper subset of $B$
Updated On: May 2, 2026
- $B \subset A$
- $A = B$
- $A' \subset B'$
- $A \subset B$
- $A \cap B = \emptyset$
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The Correct Option is D
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