Question

The four quantum numbers for the electron in the outermost orbital of potassium \((Z=19)\) are

• A. \(n=4,\ l=2,\ m=-1,\ s=+\frac{1}{2}\)
• B. \(n=4,\ l=0,\ m=0,\ s=+\frac{1}{2}\)
• C. \(n=3,\ l=0,\ m=1,\ s=+\frac{1}{2}\)
• D. \(n=4,\ l=3,\ m=-2,\ s=-\frac{1}{2}\)

Hint:

For an \(s\)-orbital, \(l=0\) and \(m=0\). Potassium has outermost electron in \(4s^1\).

Answer 1

The Correct Option is B