Question:medium

The formula to solve simple nonlinear equation \(f(x) = 0\) by Newton's Raphson Method is given by

Show Hint

Remember the formula: \(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\).
Ensure \(f'(x_n) \neq 0\) to avoid division by zero.
  • \(x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\)
  • \(x_{n+1} = x_n - \frac{f'(x_n)}{f(x_n)}\)
  • \(x_{n+1} = f(x_n) - \frac{f'(x_n)}{f'(x_n)}\)
  • \(x_{n+1} = f(x_n) - \frac{f'(x_n)}{f'(x_n)}\)
Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?
0