Question:medium

The forces of $60\text{ N}$ and $80\text{ N}$ are in equilibrium at a point, acting at an angle of $90^\circ$ to each other. Find the magnitude of the third force?

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This is a standard $(3, 4, 5)$ right-triangle ratio scaled by a factor of $20$:
$3(20) = 60\text{ N}$
$4(20) = 80\text{ N}$
$5(20) = 100\text{ N}$ (Resultant/Third force magnitude)
Updated On: Jul 7, 2026
  • $100\text{ N}$
  • $120\text{ N}$
  • $140\text{ N}$
  • $160\text{ N}$
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The Correct Option is A

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