Question

The following table gives the distribution of 100 families according to their daily expenditure: 

Expenditure (in Rs)	0–10	10–20	20–30	30–40	40–50
Number of families	14	\(x\)	27	\(y\)	15

If the mode of the distribution is \(24\), find the missing frequencies \(x\) and \(y\).

• A. \(x=16, y=20\)
• B. \(x=18, y=21\)
• C. \(x=23, y=21\)
• D. \(x=21, y=23\)

Hint:

Always start by checking if the sum of the options \(x + y\) matches the total remaining frequency.
Here, \(100 - (14 + 27 + 15) = 44\).
For Option (C), \(23 + 21 = 44\), which is correct.
This helps quickly narrow down or verify the options.

Answer 1

The Correct Option is C