The following system of equations
\[
x + y + z = 1
\]
\[
2x + 3y - mz = 2
\]
\[
3x + 5y + 3z = 3
\]
has no unique solution. Then the value of \( m \) is equal to
Show Hint
For system of equations, no unique solution \(\Rightarrow\) determinant of coefficient matrix is zero.
Step 1: Understanding the Concept:
A system of linear equations of the form AX = B has a "non-unique solution" (which means it has either no solution or infinitely many solutions) if and only if the determinant of the coefficient matrix A is equal to zero. Step 2: Key Formula or Approach:
We first write the coefficient matrix A for the given system of equations. Then, we calculate its determinant and set it equal to zero to find the value of m.
The coefficient matrix A is:
\[ A = \begin{pmatrix} 1 & 1 & 1 2 & 3 & -m 3 & 5 & 3 \end{pmatrix} \]
We need to solve the equation det(A) = 0. Step 3: Detailed Explanation:
We calculate the determinant of A by expanding along the first row:
\[ \det(A) = 1 \begin{vmatrix} 3 & -m 5 & 3 \end{vmatrix} - 1 \begin{vmatrix} 2 & -m 3 & 3 \end{vmatrix} + 1 \begin{vmatrix} 2 & 3 3 & 5 \end{vmatrix} \]
\[ \det(A) = 1((3)(3) - (-m)(5)) - 1((2)(3) - (-m)(3)) + 1((2)(5) - (3)(3)) \]
\[ \det(A) = (9 + 5m) - (6 + 3m) + (10 - 9) \]
\[ \det(A) = 9 + 5m - 6 - 3m + 1 \]
Combine the terms:
\[ \det(A) = (5m - 3m) + (9 - 6 + 1) \]
\[ \det(A) = 2m + 4 \]
For the system to have no unique solution, we set the determinant to zero:
\[ 2m + 4 = 0 \]
\[ 2m = -4 \]
\[ m = -2 \]
Step 4: Final Answer:
The value of m for which the system has no unique solution is -2.