Question:medium

The first term of an A.P. is $148$ and the common difference is $-2$. If the A.M. of first $n$ terms of the A.P. is $125$, then the value of $n$ is

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Mean of A.P. simplifies nicely to $\frac{1}{2}[2a+(n-1)d]$, no need to compute full sum.
Updated On: May 8, 2026
  • $18$
  • $24$
  • $30$
  • $36$
  • $48$
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The Correct Option is B

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