To solve this problem, we need to understand the chemical reactions involved in the given sequence.
The starting compound is a cyclohexylamine which reacts with benzoyl chloride \(C_6H_5COCl\) in the presence of sodium hydroxide (NaOH). This reaction is known as Schotten-Baumann reaction, where an amine reacts with an acid chloride to form an amide. Thus, compound [A] is a benzamide derivative as shown below:
Next, compound [A] undergoes reduction with lithium aluminium hydride \(LiAlH_4\). This is a strong reducing agent that converts amides to amines, specifically by replacing the carbonyl (=O) group with hydrogen. Therefore, the product [B] is N-benzylcyclohexylamine.
Thus, the final product [B] is correctly represented by option
