Step 1: Pick the most restrictive clue first.
Look at the row clues 3, 1, 2, 2. The number 1 for row 2 is the strictest clue, since only one cell in the whole second row is allowed to be shaded. Checking row 2 first will eliminate wrong options fastest.
Step 2: Scan row 2 of every option.
In option (i), row 2 has cells shaded in the second and fourth spot, that is 2 shaded cells, already too many. Option (iii) also shades 2 cells in row 2. So (i) and (iii) are out right away.
Option (iv) shades only 1 cell in row 2, and option (ii) also shades only 1 cell in row 2, so both survive this first check.
Step 3: Use the row 3 clue, which should be 2, to separate (ii) and (iv).
In option (ii), row 3 has 2 shaded cells, matching the clue. In option (iv), row 3 has only 1 shaded cell, which breaks the row 3 clue of 2. So option (iv) is eliminated here.
Step 4: Confirm option (ii) fully.
With (i), (iii), and (iv) eliminated, only option (ii) remains. Checking all four rows of (ii) gives 3, 1, 2, 2 and all four columns give 2, 2, 2, 2, both matching Panel I completely.
Final Answer:
\[ \boxed{\text{(ii)}} \]