Step 1: Rearrange the formula:
$\cos\theta = \frac{h\,r\,\rho\,g}{2T}$. Everything except $\rho$ is common.
Step 2: Compare:
A denser liquid gives a larger $\cos\theta$, hence a smaller angle. The densest, liquid 3, has the smallest angle and the lightest, liquid 1, has the largest. So $\theta_1 > \theta_2 > \theta_3$ (B).
Final Answer:
$\theta_1 > \theta_2 > \theta_3$.
\[ \boxed{\theta_1 > \theta_2 > \theta_3} \]