Question:medium
The events A and B are such that \(P(A)=0.7, P(B')=0.8\) and \(P(A \cup B) = 0.8\). Then \(P(A' \cup B')\) is equal to
The events A and B are such that \(P(A)=0.7, P(B')=0.8\) and \(P(A \cup B) = 0.8\). Then \(P(A' \cup B')\) is equal to
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Always keep De Morgan's laws handy: \(P(A' \cup B') = 1 - P(A \cap B)\) and \(P(A' \cap B') = 1 - P(A \cup B)\). These identities solve 90% of intersection/union probability problems.
Updated On: Jun 24, 2026
- 0.9
- 0.7
- 0.5
- 0.3
- 0.1
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The Correct Option is A
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