Question:medium

The escape velocity of a body from the surface of the earth is 11.2 km/s. If a body is projected with a velocity twice the escape velocity, then the velocity of the body far away from the earth will be:

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Energy conservation: $\frac{1}{2}mv^{2} - \frac{GMm}{R} = \frac{1}{2}mv_{\infty}^{2}$.
Updated On: Apr 8, 2026
  • 11.2 km/s
  • $11.2 \sqrt{3}$ km/s
  • $11.2 \sqrt{2}$ km/s
  • 22.4 km/s
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The Correct Option is B

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