Step 1: Circuit symmetry.
The network is symmetric about the vertical midline, placing symmetric nodes at equal potential.
Step 2: Balanced bridge elimination.
The central vertical 2 Ω resistor carries no current and can be removed.
Step 3: Simplifying upper branches.
Each side becomes series 2+2 = 4 Ω; these two 4 Ω branches are in parallel, yielding 2 Ω.
Step 4: Including the bottom resistor.
The bottom 2 Ω resistor is directly across A and B, parallel to the upper 2 Ω.
Step 5: Final parallel combination.
2 Ω ∥ 2 Ω = 1 Ω.
Step 6: Conclusion.
Equivalent resistance between A and B is 1 Ω.