Question:medium

The equilibrium constant for the disproportionation reaction
\( 2\text{Cu}^+ (aq) \rightleftharpoons \text{Cu} (s) + \text{Cu}^{2+} (aq) \)
at \( 25^\circ \text{C} \) is given that
\( E^\circ_{\text{Cu}^+/\text{Cu}} = 0.52\,\text{V}, \quad E^\circ_{\text{Cu}^{2+}/\text{Cu}^+} = 0.16\,\text{V} \).

Show Hint

Use log K=(nE^∘)/(0.0591) at 25^∘C.
Updated On: Mar 23, 2026
  • \(6\times10^4\)
  • \(6\times10^6\)
  • \(1.2\times10^6\)
  • 1.2×10⁸
Show Solution

The Correct Option is C

Solution and Explanation

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