Question:medium
The equation of the tangent to the curve $y = x^3 - 6x + 5$ at $(2, 1)$ is:
The equation of the tangent to the curve $y = x^3 - 6x + 5$ at $(2, 1)$ is:
Show Hint
Always check if the point $(2, 1)$ satisfies your final equation. $6(2) - 1 - 11 = 12 - 12 = 0$. Since it satisfies the equation, your calculation is likely correct.
Updated On: May 2, 2026
- $6x - y - 11 = 0$
- $6x - y - 13 = 0$
- $6x + y + 11 = 0$
- $6x - y + 11 = 0$
- $x - 6y - 11 = 0$
Show Solution
The Correct Option is A
Solution and Explanation
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