Question:medium
The equation of the plane containing the lines
\[
\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}
\text{and}
\frac{x-2}{2} = \frac{y-4}{3} = \frac{z-6}{5}
\]
The equation of the plane containing the lines
\[
\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}
\text{and}
\frac{x-2}{2} = \frac{y-4}{3} = \frac{z-6}{5}
\]
Show Hint
Cross product errors are common—compute carefully and verify signs.
Updated On: Apr 30, 2026
- $x + 2y + z = 0$
- $x - 2y + z = 0$
- $x - 2y - z = 0$
- $x + 2y - z = 0$
- $2y - x - z = 0$
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The Correct Option is
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