Question:medium
The equation of the plane containing the line \( \frac{x-\alpha}{l} = \frac{y-\beta}{m} = \frac{z-\gamma}{n} \) is \( a(x-\alpha)+b(y-\beta)+c(z-\gamma)=0 \), where \( al + bm + cn \) is equal to
The equation of the plane containing the line \( \frac{x-\alpha}{l} = \frac{y-\beta}{m} = \frac{z-\gamma}{n} \) is \( a(x-\alpha)+b(y-\beta)+c(z-\gamma)=0 \), where \( al + bm + cn \) is equal to
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If a line lies in a plane, its direction ratios satisfy plane equation.
Updated On: Apr 30, 2026
- \(1\)
- \(-1\)
- \(2\)
- \(8\)
- \(0\)
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The Correct Option is
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