Question:medium

The equation of the parabola with focus \((2,0)\) and vertex \((1,0)\) is

Show Hint

For a parabola opening along positive \(x\)-axis, use \((y-k)^2=4a(x-h)\), where vertex is \((h,k)\) and focus is \((h+a,k)\).
  • \(y^2=4x\)
  • \(y^2=4x-4\)
  • \(y^2=4(x+1)\)
  • \(y^2=-4(x-1)\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0