Question:medium

The equation of right circular cylinder of radius \(2\ \text{cm}\) whose axis passes through the point \((1,2,3)\) and has direction cosines proportional to \((2,-3,6)\) is:

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For a cylinder with known axis, use distance of a point from a line equal to the radius.

Updated On: May 19, 2026

\(45x^2+40y^2+13z^2+36yz+24zx+12xy+42x+280y+126z+294=0\)
\(45x^2+40y^2+13z^2+36yz-24zx+12xy-42x-280y-126z+294=0\)
\(45x^2+40y^2+13z^2+36yz-24zx-12xy+42x+280y+126z-294=0\)
\(45x^2-40y^2-13z^2+36yz-24zx-12xy+42x+280y+126z-294=0\)

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The Correct Option is B

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