Question:medium
The equation of line which is parallel to $\frac{2-x}{-3}=\frac{y-2}{2}=\frac{z-4}{1}$ and passing through the point $(1,1,1)$, is
The equation of line which is parallel to $\frac{2-x}{-3}=\frac{y-2}{2}=\frac{z-4}{1}$ and passing through the point $(1,1,1)$, is
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Logic Tip: The most common trap in 3D geometry is failing to notice reversed signs in the numerator like $(2-x)$ or $(3-2y)$. Always force the variable to have a coefficient of $+1$ before reading the direction ratios.
Updated On: Apr 27, 2026
- $\frac{x-1}{3}=\frac{y-1}{2}=\frac{z+1}{1}$
- $\frac{x-1}{3}=\frac{y-1}{2}=\frac{z-1}{1}$
- $\frac{x-1}{3}=\frac{y-1}{-2}=\frac{z-1}{1}$
- $\frac{x-1}{-3}=\frac{y-1}{2}=\frac{z-1}{1}$
- $\frac{x-1}{3}=\frac{y-1}{2}=\frac{z+1}{-1}$
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The Correct Option is B
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