Question:medium

The equation of free vibration of a system is \( X + 36\pi^2 X = 0 \). Its natural frequency is:

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The natural frequency of a free vibrating system is related to the coefficient of the second derivative term in its equation of motion.
Updated On: Feb 18, 2026
  • 4 Hz
  • 3 Hz
  • \( 6\pi \, \text{Hz} \)
  • 6 Hz
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The Correct Option is D

Solution and Explanation

Step 1: Free Vibration Equation
The free vibration equation is expressed as: \[m X'' + k X = 0\] Where \( X \) represents displacement, \( m \) is mass, and \( k \) is stiffness. For a harmonic oscillator, the natural frequency \( \omega \) is defined by: \[\omega^2 = k/m\] Given the equation \( X + 36\pi^2 X = 0 \), we obtain: \[\omega^2 = 36\pi^2\] Step 2: Natural Frequency Calculation The natural frequency \( f \) relates to \( \omega \) according to: \[f = \frac{\omega}{2\pi}\] Therefore: \[f = \frac{6\pi}{2\pi} = 6 \, \text{Hz}\] Final Answer: \[ \boxed{6 \, \text{Hz}}\]
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