Question

The equation of a line passing through the point $(-1, 2, 3)$ and perpendicular to the lines $\frac{x}{2} = \frac{y-1}{-3} = \frac{z+2}{-2}$ and $\frac{x+3}{-1} = \frac{y+3}{2} = \frac{z-1}{3}$ is

• A. $\frac{x+1}{5} = \frac{y-2}{-4} = \frac{z+3}{1}$
• B. $\frac{x+1}{5} = \frac{y+2}{4} = \frac{z+3}{1}$
• C. $\frac{x+1}{5} = \frac{y-2}{4} = \frac{z-3}{-1}$
• D. $\frac{x+1}{1} = \frac{y-2}{4} = \frac{z-3}{3}$

Hint:

To find a vector perpendicular to two others, use the Cross Product.

Answer 1

The Correct Option is C