Question:medium

The equation of a circle with center \( (5, 4) \) and touching the \( Y \)-axis is:

Show Hint

To derive the equation of a circle, substitute the center coordinates and radius into the general formula, then expand and simplify the expression.
Updated On: Mar 28, 2026
  • \( x^2 + y^2 - 10x - 8y - 16 = 0 \)
  • \( x^2 + y^2 - 10x - 8y - 16 = 0 \)
  • \( x^2 + y^2 + 10x + 8y + 16 = 0 \)
  • \( x^2 + y^2 - 10x - 8y + 16 = 0 \)
Show Solution

The Correct Option is D

Solution and Explanation

The standard form of a circle's equation is: \[ (x - h)^2 + (y - k)^2 = r^2, \] where \( (h, k) \) is the center and \( r \) is the radius. Step 1: Identify given data. The center is \( (5, 4) \), so \( h = 5 \) and \( k = 4 \). The circle touches the \( Y \)-axis, meaning the radius \( r \) equals the \( x \)-coordinate of the center, so \( r = 5 \). Step 2: Substitute values into the equation. Using the center \( (5, 4) \) and radius \( r = 5 \), the equation is: \[ (x - 5)^2 + (y - 4)^2 = 5^2. \] Step 3: Simplify the equation. Expand the binomials: \[ (x - 5)^2 = x^2 - 10x + 25, \quad (y - 4)^2 = y^2 - 8y + 16. \] Substitute these into the equation: \[ x^2 - 10x + 25 + y^2 - 8y + 16 = 25. \] Simplify: \[ x^2 + y^2 - 10x - 8y + 16 = 0. \] Step 4: Check the corresponding option. The derived equation matches option \( \mathbf{(2)} \). Final Answer: The equation of the circle is: \[ \boxed{x^2 + y^2 - 10x - 8y + 16 = 0}. \]
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