Question:medium
The energy released by $2.35\,g$ of $^{235}U$ by fission in a nuclear reactor (in $MeV$) is (Average energy released per fission is $200\,MeV$):
The energy released by $2.35\,g$ of $^{235}U$ by fission in a nuclear reactor (in $MeV$) is (Average energy released per fission is $200\,MeV$):
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Always convert mass to number of nuclei using Avogadro number.
Updated On: Apr 24, 2026
- $1.2 \times 10^{24}$
- $0.4 \times 10^{24}$
- $0.6 \times 10^{24}$
- $0.8 \times 10^{24}$
- $2.4 \times 10^{24}$
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The Correct Option is A
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