Question:medium

The energy of the second bohr orbit of the hydrogen atom is $-328 \, \text{kJ mol}^{-1}$; hence the energy of the fourth bohr orbit would be:

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To solve these quickly: if the orbit number doubles (from 2 to 4), the energy becomes $\frac{1}{2^2} = \frac{1}{4}$ of its previous value. Conversely, if the orbit number triples, the energy becomes $\frac{1}{9}$ of the original value. Always remember that energy levels get closer together as $n$ increases.
Updated On: May 13, 2026
  • $-41 \, \text{kJ/mol}$
  • $-82 \, \text{kJ/mol}$
  • $-164 \, \text{kJ/mol}$
  • $-1312 \, \text{kJ/mol}$
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The Correct Option is B

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