Question:medium

The energy of an electron in an orbit in hydrogen atom is \(-3.4\ \text{eV}\). Its angular momentum in the orbit will be:

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For hydrogen atom: \[ E_n=-\frac{13.6}{n^2}\text{ eV} \] and \[ L=n\frac{h}{2\pi}. \] Always determine \(n\) from the energy first and then substitute into the angular momentum formula.
  • \(\dfrac{3h}{2\pi}\)
  • \(\dfrac{2h}{\pi}\)
  • \(\dfrac{h}{\pi}\)
  • \(\dfrac{h}{2\pi}\)
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The Correct Option is A

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