The element with atomic number \( Z = 114 \) is known as Flerovium (Fl). This element belongs to the Carbon family in the periodic table, which contains elements with valence electron configurations in the p-block.
To determine its position and electronic configuration, we refer to the periodic table:
- Flerovium (Fl) is placed in Group 14 of the periodic table, which is the Carbon family.
- The general electronic configuration of Group 14 elements is characterized by having two electrons in the outermost p sublevel, following the s2p2 pattern.
- The electronic configuration of Flerovium is derived from the nearest noble gas configuration of Radon (Rn), followed by the addition of electrons in the 5f, 6d, 7s, and 7p orbitals:
Thus, its electronic configuration is:
[Rn] \, 5f^{14} \, 6d^{10} \, 7s^{2} \, 7p^{2}
This matches the typical configuration pattern for the elements of the Carbon family, ensuring it is indeed a part of Group 14.
Let's evaluate the options to determine the correct answer:
- Option A: Halogen family with electronic configuration [Rn] 5f146d107s27p5. This is incorrect because the valence electronic configuration 7p5 is indicative of the Halogens (Group 17).
- Option B: Carbon family with electronic configuration [Rn] 5f146d107s27p2. This is correct as it corresponds to the Carbon family (Group 14), which Flerovium belongs to.
- Option C: Oxygen family with electronic configuration [Rn] 5f146d107s27p4. This is incorrect as the valence configuration 7p4 is typical for the Oxygen family (Group 16).
- Option D: Nitrogen family with electronic configuration [Rn] 5f146d107s27p6. This is incorrect because this configuration indicates a complete p-sublevel, typical for noble gases after the Nitrogen family (Group 15).
Therefore, the correct answer is: Carbon family, [Rn] 5f146d107s27p2.