Question

The element $Z = 114$ has been discovered recently. It will belong to which of the following family/group and electronic configuration ?

• A. Carbon family, $[Rn] \, 5f^{14} 6d^{10} 7s^2 7p^2$
• B. Oxygen family, $[Rn] \, 5f^{14} 6d^{10} 7s^2 7p^4$
• C. Nitrogen family,$ [Rn] \, 5f^{14} 6d^{10} 7s^2 7p^6$
• D. Halogen family , $[Rn] \, 5f^{14} 6d^{10} 7s^2 7p^5$

Answer 1

The Correct Option is A

To determine which family/group the element with $Z = 114$ belongs to and its electronic configuration, we need to consider its position in the periodic table.

1. The atomic number $Z = 114$ corresponds to the element Flerovium (Fl).
2. We derive its position based on its atomic number in the periodic table:
   • Flerovium is a part of group 14, also known as the carbon family, in the periodic table.
3. The electronic configuration for elements with high atomic numbers is often expressed starting from the nearest noble gas, in this case, Radon ($[Rn]$). The complete electron configuration can be built as follows:
   • The electrons after Radon are filled in the following order: $5f, 6d, 7s, 7p$.
   • Thus, the electron configuration for Flerovium is $[Rn] \, 5f^{14} \, 6d^{10} \, 7s^2 \, 7p^2$.

Considering these points, the element with $Z = 114$ belongs to the carbon family, and its electronic configuration is $[Rn] \, 5f^{14} \, 6d^{10} \, 7s^2 \, 7p^2$.

Therefore, the correct answer is:

Carbon family, $[Rn] \, 5f^{14} \, 6d^{10} \, 7s^2 \, 7p^2$