Question:medium

The electric flux through the surface

Show Hint

Gauss's Law is independent of the geometry of the closed surface.
Updated On: May 14, 2026
  • in figure (c) is the largest
  • in figure (b) is same as figure (c) but is smaller than figure (d)
  • is the same for all the figures
  • in figure (d) is the least
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
The figures show various closed surfaces enclosing a charge \(+q\).
We need to determine how the electric flux depends on the shape or size of the surface.
Step 3: Detailed Explanation:
According to Gauss's Law, the total electric flux \(\phi\) through any closed surface is given by:
\[ \phi = \frac{q_{\text{enclosed}}}{\epsilon_0} \]
This law states that the flux depends only on the net charge enclosed by the surface and not on its shape, size, or orientation.
Since all the surfaces (a), (b), (c), and (d) enclose the same net charge \(+q\), the total electric flux passing through each of them must be identical.
Step 4: Final Answer:
The electric flux is the same for all the figures.
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